How to design the table of the six-team badminton single round robin match?
Option 1: Direct elimination
The 1 seed and the No.2 seed were selected according to previous competition results or lottery, and then arranged according to the following figure. Note that the 3rd and 4th seeds can be omitted for the 2nd and 7th rounds of Team 6 (this is stipulated by the rules). Use this plan to decide the top four, ***2+2+2=6 games.
Option 2: Group Single Round-robin knockout
1. Divide six teams into two groups, A\B, with three teams in each group, for a single round robin. Each team needs to participate in two games, and each group has three games. Group ranking basis: (1) according to the number of wins between teams; (2) Teams with the same number of wins are ranked according to the winning-losing relationship; (3) If multiple teams have the same number of wins and cannot be sorted according to the winning-losing relationship, they will be sorted according to the number of net wins; (4) If the net wins are the same, they shall be sorted according to the net wins; (5) If the net wins are the same, they shall be sorted according to the net win score; (6) If the net winning scores are the same, the order shall be decided by drawing lots.
2. Take the top two players in each group to enter the knockout stage, A 1 vs B2, B 1 vs A2. The winner plays the final and the loser plays the 3/4 final. ***3*2+2+2= 10 field in this scheme.
In addition, I think 1 group six single round-robin knockout is not desirable. First of all, it doesn't conform to the convention of competition arrangement. The schedule is too long, and * * * needs 15 games. It is impossible for you to add "all three games are tied", because there must be wins and losses in badminton matches, and there is no such thing as a draw. Just note that the round robin must end before the outcome is decided in advance. For example, five pairs of players play five games between the two teams, and the scores of 3:0 and 3: 1 are not counted, and they must play five games.