Six-person lottery probability

When six people line up, * * * has a stop loss method of (6,6) = 720.

Even numbers have a (3,2 2) × a (4 4,4) = 6× 24 =144 station method.

So the probability that both parties are even numbers is 144÷720= 1/5.

There are a (4,4 4) × a (5 5,2) = 24× 20 = 480 non-adjacent station methods.

So the probability that Party A and Party B are not adjacent is 480÷720=2/3.

I wish you happiness.