Logical thinking problem: three boys fell in love with a girl at the same time. In order to decide which of them can marry the girl, they decided to duel with pistols.

Three boys fell in love with a girl at the same time. In order to decide which of them can marry the girl, they decided to duel with pistols. Xiao Li's hit rate is 30%, and Xiao Huang is better than him, with a hit rate of 50%. The best shooter is Kobayashi, who never makes mistakes, and the hit rate is 100%. Because of this obvious fact, in order to be fair, they decided in this order: Xiao Li shot first, Huang Xiao second and Xiao Lin last. And so on until there is only one person left. So which of these three people has the best chance to survive? What strategies should be adopted?

Answer: Kobayashi will kill Huang when it's his turn and he's not dead, and then fight rookie Li.

So, Huang will fight Lin, if Lin is not dead, or he will die.

After calculation and comparison (the process is abbreviated), Xiao Li will decide to play Xiao Lin first.

So after calculation, Xiao Li has 873/2600≈33.6% vitality;

Huang Xiaoyou 109/260≈4 1.9% vitality;

Kobayashi has 24.5% vitality.

Oh, so Xiao Li's first shot will be shot into the air. Of course, whoever is alive will be hit in the future.

As always, Lin was beaten first, and Xiao Lin killed Huang first. The road to go is very narrow!

Finally, the survival rate of plum, yellow and forest is about 38: 27: 35;

A rookie has a great chance to survive and find a beautiful woman.

Li Xian shot an empty gun (if he works in the forest together, he will suffer the most). Huang will choose Lin to shoot (if you don't fight, you will be finished first). Lin will choose the yellow shot (after all, the hit rate is high). Li He is tied with 0.3:0.280.4.

0.3:0.60.6 lin li vs. 0.73 probability success rate.

0.3:0.40.7*0.4 probability lin li vs 0.3:0.7 * 0.6 * 0.70. 7 * 0.6 probability success rate 0.64.