When a graduate student of a certain major has a second interview, there are three examination papers. Three candidates take the exam. One person draws one and puts it back immediately, and then the other person draws it.

There are general solutions to this kind of problems, and it doesn't matter if at least one of them is mentioned. Then the easiest way is to look at his negative side, at least one negative side is all. Then the probability of getting all three papers is 1*2/3* 1/3=2/9.

Then at least one probability of not being drawn is 1-2/9=7/9.