20 14 national day Gregorian calendar

20 1 1, 20 12 and 20 13 are normal years, all of which are 365 days.

So from the national day of 20 1 1 (10 10/0) to the day before the national day of 20 1 4 (September 30th):

365×3= 1095 (days)

7 days a week, divide the total number of days by 7,

If the remainder is 0, it is Saturday.

If the remainder is 1, it is Sunday.

If the remainder is 2, it's Monday.

If the remainder is 3, it will be Tuesday.

If the remainder is 4, it will be Wednesday.

If the remainder is 5, it will be Thursday.

If the remainder is 6, it's Friday.

1095÷7= 156……3

If the remainder is 3, then September 30th is Tuesday, and June 65438+ 10/is Thursday.