China Naming Network - Eight-character lottery - Q: The question of probability has been bothering me for a long time.

Q: The question of probability has been bothering me for a long time.

The title means that one of the five tickets can win the prize.

So A draws first, and the probability of winning is 1/5. At this point, there are still four lots left. For B, there are two situations, winning and not winning. If A wins, then the probability of B winning is 0. If A doesn't win the prize, B draws one from the remaining four (including one prize). The winning probability is 1/4, but this is based on the fact that A doesn't win the prize. The winning probability of A is 1- 1/5=4/5.

If there is a third person, C, the analysis method is the same. His winning probability is 4/5 * 3/4 *1/3+0 =1/5 (probability of a failure to win * probability of b failure to win * probability of c failure to win+probability of c failure to win). In addition, in the above problems, the fairness of lottery is based on their ignorance of how to draw a lottery.

Is there anything you don't understand?

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