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Is Pingyang geomantic omen good for Guangxi guests?

This is a typical problem of flat throwing motion.

(1) Because the height determines the time, it is obtained from H = 1/2gt 2: t = √ (2h/g) = √ (2 * 500/10) =10s.

x = v 0t = 100 * 10 = 1000m

Therefore, the bomb should be dropped at a horizontal distance of 1000 meters from the enemy base target.

(2) vy = gt =10 *10 =100 m/s.

The velocity of the bomb before landing is v = √ (VX 2+vy 2) = √ (1002+1002) =141.4m/s.

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