Serial number lottery template long version

(i) Let A mean "Player A's performance number is 1", then P (a) = 1 7.

So the probability that the performance serial number of player A is 1 is 1 7...(3 points).

(ii) Let b represent "at least one of the performance serial numbers of two players, A and B, is odd",

B means "The serial numbers of the performances of A and B are even".

So p (b) = 1-p (. b) = 1-A23A 27 = 67。

Therefore, the probability that at least one of the performance serial numbers of players A and B is odd is 67...(6 points).

(iii) The possible values of x are 0, 1, 2, 3, 4, 5, …(7 points).

So P(X=0)= 12 A 27 = 2 7,

p(X = 1)= 10 A 27 = 5 2 1，

P(X=2)= 8 A 27 = 4 2 1，

P(X=3)= 6 A 27 = 1 7，

P(X=4)= 4 A 27 = 2 2 1，

P (x = 5) = 2a27 =121... (10)

So the distribution list of x is

X 012345p275214217221121... (12 points)

So ex = 0× 27+/kloc-0 /× 521+2× 421+3×17+4× 221+5×1= 53. ...