Eight teams draw lots to divide into groups.

There are three weak teams and five strong teams. There are four teams in Group A and Group B respectively. When A has two weak teams, C32 times C52=3 times 10=30. If B has two weak teams, the same as above, get 30. There are 60 situations. The probability of the first question is: 60 divided by 6 in C84 = 7. Question 2: According to the answer to the question 1, there are 30 ways to have two weak teams. When there are three weak teams, C33 times C5 1=5. There are 35 kinds that meet the requirements, 35 divided by C84 = 1/2.